At each iteration, the largest element bubbles into correct order.

The bubbling operation takes $$O(n)$$ time and this operation is performed $$n$$ times. Therefore, Bubble Sort runs in $$O(n^2)$$ time.

The swaps are performed in place. If the given array is mutable, the algorithm can be performed in constant space.

func bubbleSort(_ array: inout [Int]) -> [Int] {
for _ in 0.. array[i+1] {
array.swapAt(i, i+1)
}
}
}
return array
}

Here’s a couple of real world optimizations.

Add a counter to avoid checking the part of the list that has already been sorted.

func bubbleSort(_ array: inout [Int]) -> [Int] {
var counter = 0
for _ in 0.. array[i+1] {
array.swapAt(i, i+1)
}
}
counter += 1
}
return array
}

Add a bool to return the list if it is already sorted.

func bubbleSort(_ array: inout [Int]) -> [Int] {
var counter = 0
var inOrder = false
while !inOrder {
inOrder = true
for i in 0.. array[i+1] {
array.swapAt(i, i+1)
inOrder = false
}
}
counter += 1
}
return array
} ### David Inga

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